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What is the x- coordinate for the minimum point in the function f(x) = 4cos(2x - n) from x = 0 to x =n

A) x = 0
B) x = n/2
C) x = n/4
D) x = n
E) x = 3n/4

User TheNoob
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1 Answer

6 votes

Final answer:

The x-coordinate for the minimum point in the function f(x) = 4cos(2x - n) is x = (π + n)/2.

Step-by-step explanation:

To find the x-coordinate for the minimum point in the function f(x) = 4cos(2x - n), we need to find the value of x that corresponds to the minimum of the function. In this case, the function is a cosine function, and the minimum occurs at the point where the cosine is equal to -1. This happens when 2x - n is equal to π. Solving for x, we get x = (π + n)/2. Therefore, the x-coordinate for the minimum point is x = (π + n)/2, which is option B).

User Default Writer
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