Final answer:
The x-coordinate for the minimum point in the function f(x) = 4cos(2x - n) is x = (π + n)/2.
Step-by-step explanation:
To find the x-coordinate for the minimum point in the function f(x) = 4cos(2x - n), we need to find the value of x that corresponds to the minimum of the function. In this case, the function is a cosine function, and the minimum occurs at the point where the cosine is equal to -1. This happens when 2x - n is equal to π. Solving for x, we get x = (π + n)/2. Therefore, the x-coordinate for the minimum point is x = (π + n)/2, which is option B).