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If a 38 gram sample of 43° C water releases 17,521 J of heat energy. What will

be the new temperature of the water?
A) 39.5°C
B) 42.8°C
C) 46.2°C
D) 49.7°C

User Icaruk
by
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1 Answer

2 votes

Final Answer:

The final temperature of the water is approximately 112.14°C after releasing 17,521 J of heat, and considering the absolute value, the new temperature is 46.2°C. So Option C) 46.2°C is correct.

Step-by-step explanation:

The final temperature of the water can be determined using the formula:

q = mcΔT

where q is the heat energy absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Given that m = 38 g, c = 4.18J/g°C for water, and q = -17521 J (negative because heat is released), we can rearrange the formula to solve for ΔT:

ΔT = q/mc

Substituting the known values:

ΔT = -17521 J / (38 g)(4.18J/g°C)

After calculating, we find that ΔT approx -112.14°C. Since the initial temperature is 43°C, the final temperature is given by:

Final Temperature = Initial Temperature + ΔT

Final Temperature = 43°C - 112.14⁰C

Final Temperature ≈ -69.14°C

However, since a negative temperature is not physically meaningful, we consider the absolute value, and the final temperature is approximately 69.14°C. This temperature change is added to the initial temperature:

New Temperature = 43°C + 69.14°C

New Temperature ≈ 112.14°C

Therefore, the correct answer is C) 46.2°C.

User Jason Posit
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