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How many joules of heat are required to heat 65g lead from 22.0°C to 98.5°C?​

A) Q = (65 g) × (98.5°C - 22.0°C) × specific heat of lead
B) Q = (65 g) × (98.5°C - 22.0°C) × 4.18 J/g°C
C) Q = (65 g) × (98.5 K - 22.0 K) × specific heat of lead
D) Q = (65 g) × (98.5 K - 22.0 K) × 1.00 J/g°C

1 Answer

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Final answer:

To find out the heat required to increase the temperature of lead, use the heat formula Q = m × ΔT × c, inserting the mass of lead, temperature change, and lead's specific heat capacity.

Step-by-step explanation:

To calculate how many joules of heat are required to heat 65g of lead from 22.0°C to 98.5°C, we use the formula Q = m × ΔT × c, where Q is the heat in joules, m is the mass in grams, ΔT is the change in temperature in degrees Celsius, and c is the specific heat capacity of the material in J/g°C.

As the specific heat of lead is not provided in the options, the correct formula would need to use the specific heat capacity for lead (which is approximately 0.128 J/g°C). None of the provided options contain the correct specific heat capacity for lead. Therefore, the correct calculation would be:

Q = (65 g) × (98.5°C - 22.0°C) × specific heat of lead

The specific heat of lead should be used for the calculation, not the values provided in options B and D.

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