Final answer:
If a car traveling at 30 km/h is brought to a stop in 8 meters with a given braking force, a car traveling at 60 km/h with the same braking force will require a longer distance to stop because it has four times the kinetic energy.
Step-by-step explanation:
The question is addressing a physical concept related to the stopping distance of a car when a braking force is applied. To determine which car can be brought to a halt in shorter or longer distance, we apply the principles of kinematics and dynamics. According to the work-energy principle, the work done by the braking force in stopping the car is equal to the change in the car's kinetic energy. The kinetic energy is proportional to the square of the velocity (KE = 1/2 mv2). Therefore, a car traveling at 60 km/h will have four times the kinetic energy (since kinetic energy is proportional to the square of velocity) of a car traveling at 30 km/h, assuming the mass remains constant.
Given the same braking force, the car with greater kinetic energy (traveling at 60 km/h) must travel a greater distance to dispel the same four times energy and come to a stop. So, the correct option is D) The car traveling at 60 km/h can be brought to a halt in a longer distance. This conclusion is based on the assumption that the braking force applied is constant and the effect of other factors such as road condition and reaction time is the same for both scenarios.