Final answer:
Correct option is D). By setting up equations for the volume of water over time in two containers, we find that Container X will have less water than Container Y after 25 minutes. The correct choice is d) 25 minutes.
Step-by-step explanation:
The question is about comparing the amounts of water in two containers and determining when one will have less water than the other, given different rates of filling. To solve the problem, we need to create two equations that represent the volume of water in each container over time, and find the point in time where the volume in Container X is greater than the volume in Container Y.
Let t be the number of minutes after the containers start being filled.
Container X starts with 300 liters and is filled at a rate of 12 liters per minute, so its volume VX after t minutes is VX = 300 + 12t.
Container Y starts with 500 liters and is filled at a rate of 4 liters per minute, so its volume VY after t minutes is VY = 500 + 4t.
We want to know when VX is greater than VY, so we set up the inequality 300 + 12t > 500 + 4t.
Simplify the inequality to find t:
12t - 4t > 500 - 300
8t > 200
t > 25
Container X will have less water than Container Y after 25 minutes, which corresponds to option d).
The correct answer is d) 25 minutes.