Final answer:
The total number of joules of heat energy needed to change 150 g of ice to water at 0 °C is 50,100 J, calculated by multiplying the mass of the ice by the latent heat of fusion for water.
Step-by-step explanation:
The total number of joules of heat energy needed to change 150 g of ice to water at 0 °C can be determined using the concept of latent heat. The latent heat of fusion for water is the amount of energy required to change 1 gram of ice to water without changing its temperature. For water, this value is approximately 334 J/g. Therefore, we calculate the total energy required as follows:
Energy (J) = mass (g) × latent heat of fusion (J/g)
Energy (J) = 150 g × 334 J/g
Energy (J) = 50100 J
This is the total amount of heat energy required to convert 150 g of ice at 0 °C to water at the same temperature.