Question

Ndiba and Asanji are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. Ndiba sold 12 rolls of plain wrapping paper and 5 rolls of shiny wrapping paper for a total of $157. Asanji sold 3 rolls of plain wrapping paper and 10 rolls of shiny wrapping paper for a total of $188. Find the cost each of One roll of plain wrapping paper and one roll of shiny wrapping paper.

Answer 1

By defining a system of linear equations from the given sales information and solving the system, we find the cost of one roll of plain wrapping paper is $6, and the cost of one roll of shiny wrapping paper is $17.

Step-by-step explanation:

To solve for the cost of one roll of plain wrapping paper and one roll of shiny wrapping paper, we will use a system of linear equations based on the information provided:

Ndiba's sales: 12 rolls of plain wrapping paper and 5 rolls of shiny wrapping paper = $157

Asanji's sales: 3 rolls of plain wrapping paper and 10 rolls of shiny wrapping paper = $188

Let the cost of one roll of plain wrapping paper be x dollars and the cost of one roll of shiny wrapping paper be y dollars. We can then set up the following equations:

12x + 5y = 1573x + 10y = 188

To solve the system, we can multiply the second equation by 4 to align the coefficient of x with the first equation:

• 12x + 5y = 157
• 12x + 40y = 752

Subtract the first equation from the second equation:

• 35y = 595

Divide both sides by 35 to find the cost of one roll of shiny paper:

• y = 17

Now substitute y = 17 into either original equation to solve for x:

12x + 5(17) = 157

12x + 85 = 157

12x = 72

x = 6

The cost of one roll of plain wrapping paper is $6, and the cost of one roll of shiny wrapping paper is $17.