Final answer:
To find the wavelength of the incident light, we can use the energy of the photoelectrons and the threshold wavelength. Using the equation E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength, we can rearrange the equation to solve for the wavelength. By plugging in the values, we can calculate the wavelength of the incident light.
Step-by-step explanation:
The energy of photoelectrons emitted from a photosensitive surface is 1.56 eV and the threshold wavelength is 2500 Å. We can use the equation E = hc/λ to find the wavelength of the incident light.
First, we need to convert the energy from electron volts (eV) to joules (J). Since 1 eV is equal to 1.6 x 10^-19 J, the energy of the photoelectrons is 1.56 x 1.6 x 10^-19 J.
Next, we can rearrange the equation to solve for the wavelength:
λ = hc/E
Plugging in the values, λ = (6.626 x 10^-34 J·s × 3 x 10^8 m/s) / (1.56 x 1.6 x 10^-19 J)
Calculating this expression will give us the wavelength of the incident light.