Question

A circular sinkhole has a circumference of 75.36 meters. A week later, it has a circumference of 150.42 meters.

1) Estimate the diameter of the sinkhole each week. At first, the sinkhole has an approximate diameter of 25 meters. A week later, the diameter is about 50 meters.
2) How many times greater is this diameter of the sinkhole now compared to the previous week? The diameter of the sinkhole now is about 2 times greater compared to the previous week.

Answer 1

The estimated diameter of the sinkhole in the first week is about 24 meters, and in the second week, it is approximately 48 meters, which is about 2 times greater.

Step-by-step explanation:

To find the diameter of the sinkhole each week, we can use the formula for the circumference of a circle C = πd, where C is the circumference and d is the diameter. By rearranging the formula, we get d = C/π. Using the circumference of 75.36 meters for the first week, we estimate the diameter as follows: d = 75.36 / π ≈ 24 meters (since π ≈ 3.14). For the second week with a circumference of 150.42 meters, the diameter is d = 150.42 / π ≈ 48 meters. Regarding the question of how many times greater the diameter is in the second week compared to the first one, it is approximately 2 times greater.