Question

Time to travel 0.50 m Time to travel Acceleration Initial velocity Final 0.25 m of velocity a = (v2-v,) (t2-t,) (m/s) washers V2 2 (m/s) (m/s) (s (s) 2 0.13 0.36 1.92 2.61 The acceleration of the car with the data in the table above would be|| m/s If the applied force were cut in half, what do you predict the acceleration would be?

Answer 1

The acceleration of the car is 1.87 m/s² with the given data. If the applied force were cut in half, the predicted acceleration would be 0.936 m/s².

Step-by-step explanation:

The acceleration of the car can be found using the equation a = (v2 - v1) / (t2 - t1), where v2 is the final velocity, v1 is the initial velocity, t2 is the final time, and t1 is the initial time.

Using the values given in the table, we have v2 = 2 m/s, v1 = 0.13 m/s, t2 = 1.92 s, and t1 = 0.36 s.

Substituting these values into the equation, we get a = (2 - 0.13) / (1.92 - 0.36) = 1.87 m/s².

If the applied force were cut in half, we can use Newton's second law, F = ma, to determine the new acceleration. Since the force is directly proportional to acceleration, cutting the force in half would result in half the acceleration. Therefore, the new acceleration would be 0.5 * 1.87 = 0.936 m/s².