Question

A punter kicks a football. Its height (h) in meters, t seconds after the kick is givenby the equation: h(t) = -4.912t^2 +18.24t +0.8. The height of an approaching blocker'shands is modeled by the equation: g(t) = -1.43t+4.26, using the same time. Can theblocker knock down the punt? If so, at what time does this happen?

Answer 1

`t=\frac{-b\pm\sqrt[]{b^2-4ac}\text{ }}{2a}`
`t=\frac{19.67\text{ \pm}\sqrt[]{(19.67)^2-4\cdot4.9\cdot3.46}}{2\cdot4.9}`
`t=(19.67\pm17.86)/(9.8)`
`-`
`t_1=3.82`
`t_2=\text{ 0.1}8`