Question

According to the U. S. Department of Energy, the 2011 model of the

Chevrolet Volt has a gasoline engine equivalent fuel economy rating of 300 mi/gal.
Determine the fuel economy rating in km/L

Answer 1

To convert the Chevrolet Volt's fuel economy from 300 mi/gal to km/L, use the conversion factors to first find the equivalent distance in kilometers and then the volume in liters. The result is approximately 127.58 km/L.

Step-by-step explanation:

The question asks us to convert the fuel economy rating of the 2011 Chevrolet Volt from miles per gallon (mi/gal) to kilometers per liter (km/L). To convert 300 mi/gal to km/L, we will use the following equivalences: 1 mile = 1.60934 kilometers and 1 gallon = 3.78541 liters.

First, convert miles to kilometers:
300 mi × 1.60934 km/mi = 482.802 km.

Then, convert gallons to liters:
1 gal × 3.78541 L/gal = 3.78541 L.

Now, calculate the fuel economy in km/L:
Fuel Economy = 482.802 km / 3.78541 L ≈ 127.58 km/L.

Note: The result is rounded to two decimal places for precision.