Answer:
0.1938 = 19.38% probability that a package is delivered by UPS if it weighs 2 lbs or more
Explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
![P(B|A) = (P(A \cap B))/(P(A))](https://img.qammunity.org/2022/formulas/mathematics/college/r4cfjc1pmnpwakr53eetfntfu2cgzen9tt.png)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: It weighs 2 lbs or more
Event B: Delivered by UPS
15% of the packages that are delivered by UPS weighs 2 lbs or more.
This means that
![P(A \cap B) = 0.15](https://img.qammunity.org/2022/formulas/mathematics/college/a6zflk3bpmf2kg8178ip2wz7yv9b3qlijd.png)
More than 2 lbs:
15% of 20%(UPS)
93% of 80%(Not delivered by UPS). So
![P(A) = 0.15*0.2 + 0.93*0.8 = 0.774](https://img.qammunity.org/2022/formulas/mathematics/college/ps3pzimzru71upmateggucr0sy8jrapo5g.png)
a. What is the probability that a package is delivered by UPS if it weighs 2 lbs or more
![P(B|A) = (P(A \cap B))/(P(A)) = (0.15)/(0.774) = 0.1938](https://img.qammunity.org/2022/formulas/mathematics/college/h8oap4rhkmeghj8mdlraf0rbbt4ml7pzp5.png)
0.1938 = 19.38% probability that a package is delivered by UPS if it weighs 2 lbs or more