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How much energy is needed for 2.40 kg of water to go from -6.00 °C to 61.0 °C?

A) 339.75 kJ
B) 449.28 kJ
C) 542.82 kJ
D) 675.60 0 kJ

User Obotezat
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1 Answer

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Final answer:

The energy needed for the water to change temperature is approximately 545,314.4 J.

Step-by-step explanation:

To calculate the energy needed for the water to change temperature, we can use the formula: Q = mcΔT, where Q is the energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the temperature change.

Using the given values: m = 2.40 kg, ΔT = (61.0 °C) - (-6.0 °C) = 67.0 °C, and the specific heat capacity of water c = 4186 J/kg°C, we can substitute these values into the formula. the world line of a particle provides a broader perspective in spacetime. A stationary particle has a world line that is a vertical line parallel to the time axis, while the world line for a particle with constant velocity is a straight line inclined to the time axis

Q = (2.40 kg)(4186 J/kg°C)(67.0 °C) = 545,314.4 J.

User KifoPL
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