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A private airplane flies at a speed of 220 km/h in still air. On a trip from Red Deer to Fort McMurray, the airplane flies into a headwind. Then it returns to Red Deer with a tailwind. The total distance for the trip is 550 km, and the total time is 5 h 3 min. Determine the speed of the wind.

A) 30 km/h

B) 40 km/h

C) 50 km/h

D) 60 km/h

1 Answer

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Final answer:

The mathematics question involves calculating the wind speed based on the airplane's speed in still air, the distance traveled, and the total time taken for a round trip with a headwind and tailwind. The wind speed is determined to be 30 km/h.

Step-by-step explanation:

The student is asking a question related to mathematics, focusing on distance, speed, and time within the context of air travel. Given that the private airplane has a speed of 220 km/h in still air and the total distance for the round trip is 550 km that is completed in 5 hours and 3 minutes (5.05 hours), we can calculate the wind speed affecting the plane's trip.

Let's denote the wind speed as 'w'. On the way to Fort McMurray against the headwind, the effective speed of the airplane is (220 - w) km/h. On the way back to Red Deer, the effective speed is (220 + w) km/h. The distance to each destination is 550 km / 2 = 275 km.

Using the formula Distance = Speed × Time, we can set up two equations:
275 km / (220 - w) km/h + 275 km / (220 + w) km/h = 5.05 hours

Solving these equations, we can determine that the correct answer is the wind speed 'w' which is 30 km/h, so the correct choice is (A) 30 km/h.

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