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The amount of a radioactive isotope at time t is given by A(t) = 700e^(-0.02832t) grams. The initial amount is 700 grams. How many grams remain after 30 years?

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Final answer:

Approximately 299.18 grams of the radioactive isotope remain after 30 years, calculated using the provided decay function and substituting 30 for the time variable.

Step-by-step explanation:

The question asks us to determine the amount of a radioactive isotope remaining after 30 years given the exponential decay function A(t) = 700e^(-0.02832t), where A(t) represents the amount after time t, given in years. To calculate the amount remaining, we substitute 30 for t:

A(30) = 700e^(-0.02832 × 30)

We can now evaluate this expression:

A(30) = 700 × e^(-0.8496)

Using a calculator to find e^-0.8496 (assuming an understanding of how to use the inverse logarithm function), we get approximately:

A(30) ≈ 700 × 0.4274

Thus, the approximate amount remaining after 30 years is:

A(30) ≈ 299.18 grams

Therefore, approximately 299.18 grams of the radioactive isotope remain after 30 years.

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