Final answer:
The least number of people in a marching band that satisfies the given conditions is found to be 11.
Step-by-step explanation:
The problem presented involves finding the smallest number of people in a marching band that can’t line up evenly in groups of 3 or 4, with respectively 2 and 3 left over. This is a problem that can be solved using number theory and the concept of least common multiple (LCM).
Step-by-step explanation:
Let the number of people in the band be n. We can express the problem mathematically as the following two equations:
n mod 3 = 2, which means when n is divided by 3, the remainder is 2.
n mod 4 = 3, which means when n is divided by 4, the remainder is 3.
To solve this, start with the knowledge that n = 3k + 2 for some integer k.
Check multiples of 3 plus 2 (5, 8, 11, 14, ...) until you find one that also satisfies n mod 4 = 3.
Through trial and error, n = 11 is the first number to satisfy both conditions. Therefore, the band has 11 members.