Question

An object accelerates to a velocity of 250 m/s over a time of 3.6 s. The acceleration it experienced was 47 m/s². What was its initial velocity?

Answer 1

The initial velocity of the object was 80.8 m/s, which is calculated using the equation of motion v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Step-by-step explanation:

To calculate the initial velocity of an object given the final velocity, acceleration, and time, we can use one of the equations of motion: final velocity (v) = initial velocity (u) + acceleration (a) × time (t). In this case, we are given the final velocity (250 m/s), the acceleration (47 m/s²), and the time (3.6 s). To find the initial velocity (u), we can rearrange the equation to: initial velocity (u) = final velocity (v) - acceleration (a) × time (t).

Now plugging in the values, we get: u = 250 m/s - (47 m/s² × 3.6 s). This equals 250 m/s - 169.2 m/s, which gives us an initial velocity of 80.8 m/s.