Final answer:
The car would move a distance of 9.6 meters. The displacement of the car is 25 meters. It would take 1500 seconds for the spacecraft to stop.
Step-by-step explanation:
To find the distance a car moved, you can use the equation: distance = velocity x time. In this case, the initial velocity of the car is 14.0 m/s and the final velocity is 16.0 m/s. The time is given as 4.8 s.
Plugging in the values, we get: distance = (16.0 m/s - 14.0 m/s) x 4.8 s = 9.6 meters. Therefore, the car would move a distance of 9.6 meters.
For the displacement of a car accelerating from 15 m/s forward to 10 m/s forward in 8.0 s, we can use the equation: displacement = (initial velocity + final velocity) x time / 2.
Plugging in the values, we get: displacement = (15 m/s + 10 m/s) x 8.0 s / 2 = 25 meters. Therefore, the displacement of the car is 25 meters.
To calculate the time it would take for Apollo 10's spacecraft to stop in a distance of 3.0 x 10^6 m, we can use the equation: time = distance / velocity.
Plugging in the values, we get: time = 3.0 x 10^6 m / 39,897 km/h = 1500 seconds. Therefore, it would take 1500 seconds for the spacecraft to stop.