Final answer:
The correct statement is A only. The image of the pin cannot be seen through AB, BC, or DC.
Step-by-step explanation:
Based on the information provided, the correct statement is A only. When light travels from a medium with a lower refractive index (such as air) to a medium with a higher refractive index (such as glass), it undergoes refraction. The critical angle is the angle of incidence at which the refracted ray is directed along the boundary between the two media, resulting in total internal reflection. In this case, since the pin P is placed closer to the face AD of the rectangular glass block, it is not within the critical angle range, so the image of P cannot be seen through AB, BC, or DC.