Question

A curler pushes a stone 7.2m at a constant velocity and then lets go so it glides 4m onto a target. The friction from the ice provides deceleration of 1.6 m/s squared. How long did the curler push the stone for?

Answer 1

The curler pushed the stone for approximately 0.625 seconds.

Step-by-step explanation:

To find out how long the curler pushed the stone for, we can first calculate the initial velocity of the stone.

Given:

• Distance pushed by the curler: 7.2 m
• Friction-provided deceleration: 1.6 m/s²
• Distance the stone glides after being pushed: 4 m

Since the stone glides at constant velocity after being pushed, we can calculate its initial velocity using the equation:

initial velocity (v₀) = (deceleration × distance pushed) + final velocity

Since the final velocity is 0 (as the stone comes to a stop), we have:

initial velocity = (1.6 m/s² × 7.2 m) + 0 = 11.52 m/s

Now, we can calculate the time it took for the curler to push the stone by using the equation:

time (t) = distance pushed / initial velocity

Plugging in the values, we get:

time = 7.2 m / 11.52 m/s ≈ 0.625 s