Question

What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?

O x=-4+25
O x=-4 48
O x= -823
O x= -47413

Answer 1

The zeros of the function f(x) = x^2 + 8x + 4 are -4 + 2√3 and -4 - 2√3.

Step-by-step explanation:

The zeros of the function f(x) = x2 + 8x + 4 can be found by setting the function equal to zero and solving for x. The equation is x2 + 8x + 4 = 0. We can solve this quadratic equation using the quadratic formula:

x = (-b ± √(b2 - 4ac)) / 2a

In this case, a = 1, b = 8, and c = 4. Plugging these values into the quadratic formula, we get:

x = (-8 ± √(82 - 4(1)(4))) / (2(1)

x = (-8 ± √(64 - 16)) / 2

x = (-8 ± √48) / 2

x = (-8 ± 4√3) / 2

We can simplify this further:

x = -4 ± 2√3

Therefore, the zeros of the function f(x) = x2 + 8x + 4 are x = -4 + 2√3 and x = -4 - 2√3.