Main Answer:
By considering initial acceleration and subsequent deceleration phases in motion analysis.The total distance traveled is 480 meters (b).
Explanation:
When analyzing the motion, we need to consider the two phases: the initial acceleration and the subsequent deceleration. In the first 8 seconds, you're accelerating at a rate of -50 m/s². The formula for distance covered during constant acceleration is given by
, where
is the initial velocity,
is the time, and
is the acceleration. In this case,
,
, and
. Plugging these values in, we get
. Calculating this yields

Now, during the deceleration phase, you slow to a stop in 60 meters. The formula
can be used to find the distance covered during deceleration, where
is the final velocity,
is the initial velocity, and
is the acceleration. Here,
,
, and
is what we need to find. Rearranging the formula to solve for
, we get
. Substituting the values, we find
,

Now, applying this deceleration to the remaining time of 8 seconds, we use the formula
again, where
is the initial velocity,
is the time, and
is the acceleration. This time
and
. Plugging in these values, we find

Adding the two distances
we get
. However, distance cannot be negative, so we take the absolute value, yielding
which is equivalent to

Therefore, The correct answer is the total distance traveled is 480 meters (b).