Final answer:
To solve the quadratic equation 4x^2 + 72x + 320 = 0, use the quadratic formula and simplify to find the solutions as -10 and -8.
Step-by-step explanation:
To solve the quadratic equation 4x^2 + 72x + 320 = 0, we can use the quadratic formula. The quadratic formula is x = (-b ± sqrt(b^2 - 4ac)) / (2a). In this equation, a = 4, b = 72, and c = 320. Plugging in these values into the quadratic formula, we get x = (-72 ± sqrt(72^2 - 4*4*320)) / (2*4). Simplifying further, x = (-72 ± sqrt(5184 - 5120)) / 8. Now, calculating the values inside the square root, x = (-72 ± sqrt(64)) / 8. Taking the square root of 64, we get x = (-72 ± 8) / 8. Simplifying, x = -9 ± 1. So the solutions to the equation are x = -10 and x = -8. Therefore, the solutions from least to greatest are -10 and -8.