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A powder sample weighing 250 g and having a surface area of 1 m2/g is dispersed in 1 L of water. After 10 minutes, 0.4 g of the sample is dissolved. The aqueous solubility of the sample is 0.01 g/cm3. a) Calculate k. Assume that sink conditions are prevailing and that the surface area of the sample is constant. b) How long will the sink conditions prevail

User Mir Adnan
by
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1 Answer

3 votes

Answer:

a)


K = 2.64 * 10^(-8)

b)


15 (5)/(8) hours

Step-by-step explanation:

Given

Surface Area (S) of 250 grams of powder sample
= 250 square meter.


S = 2500000 square centimeter


V(dC)/(dT) = 0.40 grams/minute


V(dC)/(dT) = (dM)/(dT) = (0.40*60)/(10) = 0.66 mg per second


C_s = 0.01 gram per cubic meter
= 10 mg/ml

a)


(dM)/(dT) = K SC_s


0.66 = K* 2500000* 10\\


K = 2.64 * 10^(-8) cm /sec

b) Time taken

Time taken to sink


(10*60)/(0.4) * 37.5 = 56,250

Time in hours


15 (5)/(8) hours

User Oliver Burdekin
by
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