Question

At a recent Vikings game, 5445 admission tickets were taken in. The cost of a student ticket was $1.50, and the cost of a non-student ticket was $2.50. A total of 232 tickets were sold. How many students and how many non-students attended the game?

A. 92 students and 140 non-students
B. 140 students and 92 non-students
C. 116 students and 116 non-students
D. 80 students and 152 non-students

Answer 1

To solve the problem, a system of equations was set up with two unknowns: the number of student and non-student tickets. By using the total number of tickets and the total revenue, the equations were solved to find that 140 student tickets and 92 non-student tickets were sold.

Step-by-step explanation:

The question involves setting up and solving a system of equations to determine the number of student and non-student tickets sold. We have two equations from the information given:

1. The total number of tickets sold is 232.
2. The total revenue from all tickets sold is $5445.

Let s represent the number of student tickets sold at $1.50 each, and n represent the number of non-student tickets sold at $2.50 each. We can then set up the following system of equations:

1. s + n = 232
2. 1.50s + 2.50n = 5445

By solving this system, we can determine the correct number of student and non-student tickets.

First, multiply the second equation by 2 to get rid of decimals:

1. 2(1.50s) + 2(2.50n) = 2(5445)

Which simplifies to:

1. 3s + 5n = 10890

Next, solve the first equation for s:

1. s = 232 - n

By substituting this into the second equation, we get:

1. 3(232 - n) + 5n = 10890

Solving for n, we find n = 140. Then we calculate s = 232 - 140 to find s = 92.

Therefore, the answer is B. 140 students and 92 non-students attended the game.