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Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, ranging from heights of 136 to 194 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.72 cm, y = 81.43 kg, r = 0.339, P-value = 0.001, and ŷ = 106 + 1.13x. Find the best-predicted value of ý (weight) given an adult male who is 162 cm tall. Use a 0.01 significance level. The best-predicted value of y for an adult male who is 162 cm tall is (Round to two decimal places as needed.)

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Final answer:

The regression equation provided is ŷ = 106 + 1.13x, and using it to predict the weight for a 162 cm tall male yields a value of 289.06 kg, which appears to be incorrect due to potential issues with units or a typo in the regression equation.

Step-by-step explanation:

The question deals with finding the best-predicted weight of an adult male given his height using a regression equation. The regression equation provided is ŷ = 106 + 1.13x, where x is the height in cm and ŷ is the predicted weight in kg. To find the predicted weight for a male who is 162 cm tall, substitute x = 162 into the equation:

ŷ = 106 + 1.13(162)

ŷ = 106 + 183.06

ŷ = 289.06

Therefore, the best-predicted weight for an adult male who is 162 cm tall is 289.06 kg. This result seems incorrect; as usually, adult males do not weigh that much. There might have been a misunderstanding of the units for the intercept or slope, or a typo in the provided regression equation. Without clarification or additional context for the appropriate units or correct values, the given predicted value cannot be accurate.

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