Question

A juggler tosses a ball into the air. The balls height, h, feet and time, t, seconds can be represented by the equation h(t)=-16t² +144.

After 15 seconds what was the height of the ball?

Answer 1

The height of the ball after 15 seconds is -3456 feet.

Step-by-step explanation:

The height of the ball, h(t), after 15 seconds can be found by substituting t=15 into the equation h(t)=-16t²+144:

h(15) = -16(15)² + 144

h(15) = -16(225) + 144

h(15) = -3600 + 144

h(15) = -3456

Therefore, after 15 seconds, the height of the ball is -3456 feet.