Question

Part 1 (1 point) See If a 53.7 mg sample of protein A in 1.5 mL of water has an osmotic pressure of 0.273 atm, what is the molar mass of protein A? g/mol Part 2 (1 point) See HD If a 54.9 mg sample of protein Bin 1.75 mL of water has an osmotic pressure of 0.218 atm, what is the molar mass of protein B? g/mol

Answer 1

To calculate the molar mass of proteins A and B, first convert the given masses to grams, volumes to liters, and apply the osmotic pressure formula II = (n/V)RT. Then, solve for n (moles of solute) and divide the mass of each protein by its moles to find the molar mass.

Step-by-step explanation:

To calculate the molar mass of the proteins A and B based on osmotic pressure, we can use the formula:

II = (n/V)RT

where II is the osmotic pressure, n is the number of moles of solute, V is the volume of solution in liters, R is the ideal gas constant, and T is the temperature in Kelvin.

First, for protein A, we convert the mass of protein to grams (53.7 mg = 0.0537 g) and the volume to liters (1.5 mL = 0.0015 L), then rearrange the formula to solve for n:

n = II * V / RT

n = 0.273 atm * 0.0015 L / (0.0821 L·atm / K·mol * 298 K)

After calculating n, we find the molar mass by dividing the mass of protein A by the number of moles n:

Molar Mass A = mass of A / n

Repeat this process for protein B with its respective mass (54.9 mg = 0.0549 g), volume (1.75 mL = 0.00175 L), and osmotic pressure (0.218 atm).