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Solve the inequality ||x - 5| + 2| ≤ 3 for x. Which values of x satisfy this inequality?

Option 1: x ≤ 1
Option 2: x ≥ 7
Option 3: 2 ≤ x ≤ 4
Option 4: -1 ≤ x ≤ 9

1 Answer

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Final answer:

To solve the inequality ||x - 5| + 2| ≤ 3 for x, we consider different cases depending on the signs of |x - 5| and |. The solutions are x ≤ 1, x ≥ 7, or 2 ≤ x ≤ 4.

Step-by-step explanation:

To solve the inequality ||x - 5| + 2| ≤ 3 for x, we need to consider the different cases depending on the signs of |x - 5| and |. First, let's consider the case when both |x - 5| and | are positive. In this case, the inequality becomes (x - 5) + () ≤ 3. Simplifying this, we get x + - 5 + () ≤ 3. Now, let's consider the case when both |x - 5| and | are negative. In this case, the inequality becomes -(x - 5) + () ≤ 3. Simplifying this, we get -x + 5 + () ≤ 3.

Now, let's solve each of these inequalities separately:

Case 1: x + - 5 + () ≤ 3

To simplify this inequality further, we need to consider different subcases depending on the values of x:

Subcase 1.1: x - 5 ≥ 0 and ≥ 0

In this subcase, the inequality becomes x - 5 + ≤ 3. Combining like terms, we get x ≤ 1.

Subcase 1.2: x - 5 < 0 and < 0

In this subcase, the inequality becomes -x + 5 + ≤ 3. Combining like terms, we get x ≥ 7.

Subcase 1.3: x - 5 < 0 and ≥ 0

In this subcase, the inequality becomes -x + 5 + () ≤ 3. Combining like terms, we get x ≥ 2.

Subcase 1.4: x - 5 ≥ 0 and < 0

In this subcase, the inequality becomes x - 5 + () ≤ 3. Combining like terms, we get x ≤ 4.

Case 2: -x + 5 + () ≤ 3

To simplify this inequality further, we need to consider different subcases depending on the values of x:

Subcase 2.1: x - 5 ≥ 0 and ≥ 0

In this subcase, the inequality becomes -x + 5 + ≤ 3. Combining like terms, we get x ≤ 1.

Subcase 2.2: x - 5 < 0 and < 0

In this subcase, the inequality becomes x - 5 + ≤ 3. Combining like terms, we get x ≥ 7.

Subcase 2.3: x - 5 < 0 and ≥ 0

In this subcase, the inequality becomes -x + 5 + () ≤ 3. Combining like terms, we get x ≥ 2.

Subcase 2.4: x - 5 ≥ 0 and < 0

In this subcase, the inequality becomes -x + 5 + () ≤ 3. Combining like terms, we get x ≤ 4.

Now, let's put all the solutions together:

x ≤ 1 OR x ≥ 7 OR 2 ≤ x ≤ 4.

User LHM
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