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If your hose puts out 25.50 mL in 2.200 seconds, how many days would it take to fill a 21,000.0 gallon pool? ​

User Beahacker
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Final answer:

To fill a 21,000.0 gallon pool, we convert the pool volume to milliliters and the hose output to milliliters per day, then divide the pool volume by the daily output. It would take approximately 95.50 days to fill the pool using the specified hose.

Step-by-step explanation:

The question asks for the time it would take to fill a 21,000.0 gallon pool at a rate of 25.50 mL every 2.200 seconds. First, we need to convert the rates and volumes to compatible units. To do this, we convert 21,000.0 gallons to liters (since 1 gallon = 3.78541 liters) and then to milliliters. Next, we determine the fill rate per day by converting 25.50 mL/2.200 seconds to mL/second and then to mL/day. Finally, we divide the total volume of the pool in mL by the fill rate per day to find out how many days it would take to fill the pool.

Let's convert gallons to milliliters: 21,000 gallons * 3.78541 liters/gallon * 1000 mL/liter = 79,453,610 mL

Now find the rate in mL/day: (25.50 mL / 2.200 seconds) * (60 seconds/minute) * (60 minutes/hour) * (24 hours/day) = 831,818.18 mL/day

Last, we calculate the number of days: 79,453,610 mL / 831,818.18 mL/day ≈ 95.50 days

Therefore, it would take approximately 95.50 days to fill a 21,000.0 gallon pool using a hose with the given flow rate.

User Eyoab
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