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The probability that an individual is left-handed is 0.19. In a class of 23 students, what is the probability of finding five left-handers?

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Final answer:

The probability of finding five left-handers in a class of 23 students is 0.064.

Step-by-step explanation:

To find the probability of finding five left-handers in a class of 23 students, we can use the binomial probability formula. The formula is:

P(X=k) = C(n,k) * p^k * (1-p)^(n-k)

where P(X=k) is the probability of having exactly k successes, C(n,k) is the number of ways to choose k successes out of n trials, p is the probability of success, and n is the number of trials.

In this case, the probability of finding a left-hander is 0.19, so p = 0.19. We want to find the probability of finding exactly 5 left-handers, so k = 5. Since we have 23 students in total, n = 23. Plugging these values into the formula, we get:

P(X=5) = C(23,5) * 0.19^5 * (1-0.19)^(23-5) = 0.064

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