Final answer:
The question pertains to the physics of projectile motion, focusing on the parameters of initial velocity, total time of flight, and maximum height for two footballs kicked from opposite ends of a field. Player B kicks the ball with twice the initial velocity of Player A. The calculations for these parameters would be based on projectile motion formulas, but specific numerical values cannot be provided without additional data.
Step-by-step explanation:
The scenario described in the question involves concepts of projectile motion in physics. Since Player A kicks the ball to reach the maximum distance, we assume that the ball was kicked at a 45-degree angle; this angle maximizes range in projectile motion without air resistance. Given that the field is 100 meters long and the balls are kicked from opposite ends, both balls traverse the entire field. We are not given specific initial velocities, but Player B's is twice that of Player A.
For Player A's initial velocity (vA0), we would use the projectile motion equations to solve for initial velocity, time of flight, and maximum height based on the information provided. This answer provides an approach rather than specific numerical answers due to the lack of complete information. Player B's initial velocity (vB0) would simply be double that of Player A (2 * vA0).
The time of flight for both balls would be the same since they both hit the ground simultaneously and no air resistance or other forces are considered. The total time is calculated using the vertical component of the velocity and the acceleration due to gravity.
The maximum height each ball reaches can be calculated using the vertical component of the initial velocity and the acceleration due to gravity. Since Player B's ball has a higher initial velocity, it would reach a greater maximum height than Player A's.