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What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3 joules and the temperature rises 15.0 °C?

A) 0.163 J/g°C
B) 0.243 J/g°C
C) 0.355 J/g°C
D) 0.427 J/g°C

1 Answer

5 votes

Final answer:

To find the specific heat capacity of silver metal, the formula q = mcΔT is used. The specific heat is calculated to be 0.0573 J/g°C, which doesn't match the given options or the known specific heat of silver, which is 0.233 J/g°C.

Step-by-step explanation:

To calculate the specific heat capacity of silver metal, we use the formula:

q = mcΔT

Where q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Rearranging the formula to find c, we get:

c = q / (mΔT)

Using the provided values:

  • q (heat absorbed) = 47.3 J
  • m (mass of silver) = 55.00 g
  • ΔT (change in temperature) = 15.0 °C

We substitute in the values:

c = 47.3 J / (55.00 g × 15.0 °C)

After performing the calculation, we find:

Specific Heat Capacity of Silver = 0.0573 J/g°C

While the calculated value does not match any of the options given in the multiple-choice question, we do know (from the provided reference) that the specific heat of Ag is typically 0.233 J/g°C. Thus, it seems there was an error with the question or in the calculation process, as the correct known value was not among the offered choices.

User Bernard Covic
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