Final answer:
To calculate the HST's tangential speed, the orbital velocity formula is used with Earth's mass and the combined radius of Earth and HST's altitude.
Step-by-step explanation:
The question at hand involves calculating the tangential speed of the Hubble Space Telescope (HST) which orbits at 569 km above Earth's surface. To find the tangential speed, we use the formula for orbital velocity (v) given by v = √{γM / r}, where γ is the gravitational constant (6.674×10-11 N(m/kg)2), M is the mass of the Earth, and r is the radius of orbit. The Earth's mass (M) is 5.97 x 1024 kg, the Earth's radius is 6.38 x 106 m, and the HST's orbital radius is Earth's radius plus the altitude of HST, totaling 6.947 x 106 m. Substituting these values in the formula, we get the tangential speed of HST.