Question

A binomial probability experiment is conducted with given parameters. Compute the probability of x successes in the n independent trials of the experiment. n=7, p=0.6, x=3.

A. 0.2765
B. 0.5136
C. 0.5645
D. 0.1024

Answer 1

The probability of 3 successes in 7 trials of a binomial probability experiment with parameters n=7, p=0.6, and x=3 is 0.1024.

Step-by-step explanation:

To compute the probability of x successes in the n independent trials of a binomial probability experiment, we can use the formula:

P(X = x) = (nCx) * p^x * q^(n-x)

In this case, n = 7, p = 0.6, and x = 3. So, the probability of 3 successes in 7 trials would be:

P(X = 3) = (7C3) * (0.6^3) * (0.4^4) = 0.1024

Therefore, the correct answer is D. 0.1024.