Question

A company produces two types of jackets; windbreakers and rainbreakers. The company has at most 61 hours of finishing time per week and 67 hours of packaging time per week. Each windbreaker jacket takes 59 minutes of finishing time and 21 minutes of packaging time per week, whereas each rainbreaker jacket takes 58 minutes of finishing time and 34 minutes of packaging time per week. The company's profit for each windbreaker and rainbreaker jacket is 28 and 41, respectively. Let x denote the number of windbreaker jackets they should produce and y denote the number of rainbreaker jackets they should produce. The company wants to maximize profit. Set up the Linear Programming Problem for this situation.

Answer 1

Max p = 28x + 41y

Subject to

59x + 58y ≤ 3660

21x + 34y ≤ 4020

x ≥ 0, y ≥ 0

Explanation:

As given ,

Windbreakers Rain breakers Total

Finishing time 59 min 58 min 61 hr

Packaging time 21 min 34 min 68 hr

Profit 28 41

Let

The number of windbreaker jackets they should produce = x

The number of rain breaker jackets they should produce = y

As given,

The company wants to maximize profit.

⇒ Maximum Profit , p = 28x + 41 y

Now,

As 1 hour = 60 min

⇒61 hours = 61×60 = 3660 min

and 67 hours = 67×60 = 4020 min

∴ we get

The equations become

59x + 58y ≤ 3660

21x + 34y ≤ 4020

x ≥ 0, y ≥ 0

So, the Linear Programming Problem (LPP) for this problem is -

Max p = 28x + 41y

Subject to

59x + 58y ≤ 3660

21x + 34y ≤ 4020

x ≥ 0, y ≥ 0