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Three resistors are placed in series. They have the following resistances: R4 = 20 ohms, R2 = 20 ohms, R = 10 ohms. What current would be moved through this circuit by a 5-V power supply? Can you please show your work ???

A) 1.0 A
B) 0.10 A
C) 0.25 A
D) 0.50 A

1 Answer

1 vote

Final answer:

To calculate the current through a series circuit, we add up the resistances to find the total resistance and then apply Ohm's Law. With resistors of 20 ohms, 20 ohms, and 10 ohms, and a 5-V power supply, the current through the circuit is 0.10 A.

Step-by-step explanation:

The question asks about calculating the current through a series circuit with specified resistances. When we have three resistors in series, we simply add up their resistance values to get the total resistance of the circuit. The resistors mentioned are R4 = 20 ohms, R2 = 20 ohms, and R = 10 ohms, giving us a total resistance (Rtotal) of 50 ohms.

Using Ohm's Law (V = IR), where V is voltage, I is current, and R is resistance, we can solve for the current (I) by rearranging the formula to I = V / R. With a 5-V power supply, the current through the circuit will be I = 5 V / 50 Ω = 0.10 A.

Therefore, the correct answer is B) 0.10 A.

User Laph
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