Final answer:
To transform System A into System B, we perform the transformation: Equation (A1) + Equation (A2) → Equation [82].
To transform System B into System C, the transformation required is: Equation (B2) + Equation (B1) → Equation (C1).
Explanation:
For transforming System A into System B, let's consider the given equations:
- Equation [A1]: -4x + 3y = 15
- Equation [A2]: 5x - 2y = -17
To achieve System B from System A, we apply the operation of adding Equation (A1) to Equation (A2). By doing so, we obtain Equation [82]:
![\[ \text{Equation [A1]} + \text{Equation [A2]} \rightarrow \text{Equation [82]} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/e718vgy6gq7wp248ojm9vhak96h9r37f4t.png)
(-4x + 3y) + (5x - 2y) = 15 - 17
x + y = -2
To transform System B into System C:
- Equation [31]: 8x - 6y = -30
- Equation [82]: x + y = -2
The necessary transformation involves adding Equation (B2) to Equation (B1) to obtain Equation [C1]:
![\[ \text{Equation (B2)} + \text{Equation (B1)} \rightarrow \text{Equation [C1]} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/7mhdy06477p310x2nhkccvrhd3wc9un2ik.png)
(x + y) + (8x - 6y) = -2 - 30
9x - 5y = -32
These transformations are fundamental in solving systems of linear equations by manipulating equations to eliminate variables and ultimately find the solution set that satisfies all the given equations simultaneously.