Question

For the reaction shown, calculate how many moles of NH3 form when each amount of reactant completely reacts.

3N2H4 (1) + 4NH3(g) + N2 (g)
6.3 x 10-2 mol N2H4
Express your answer using two significant figures.
A) 8.4 x 10-2 moles NH3
B) 4.2 x 10-2 moles NH3
C) 3.2 x 10-2 moles NH3
D) 2.1 x 10-2 moles NH3

Answer 1

In this reaction, when 6.3 x 10^-2 mol of N2H4 is completely reaction, 8.4 x 10^-2 moles of NH3 are formed.

Step-by-step explanation:

The balanced chemical equation for the reaction is:

3N2H4 (1) + 4NH3(g) + N2 (g) → 6NH3 (g)

In the given reaction, it is given that 6.3 x 10^-2 mol of N2H4 is reacting completely.

From the balanced equation, the mole ratio between N2H4 and NH3 is 3:4. Therefore, by using this ratio, we can calculate the number of moles of NH3 formed:

Moles of NH3 = (6.3 x 10^-2 mol N2H4) * (4 mol NH3/3 mol N2H4)

Calculating this:

Moles of NH3 = (6.3 x 10^-2) * (4/3)

Moles of NH3 = 8.4 x 10^-2

Therefore, the correct answer is A) 8.4 x 10^-2 moles NH3