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Order the following from least to greatest:

8, 7, Square root of 68, 9
A) 7, 8, 3√17, 9
B) √68, 7, 8, 9
C) 7, √68, 8, 9
D) 7, 8, √68, 9

User Alex Aung
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1 Answer

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Final answer:

The correct order from least to greatest is 7, 8, √68, 9. Given that √68 is between 8 and 9, the sequence matches choice D.

Step-by-step explanation:

To order the numbers from least to greatest, we first need to evaluate the square root of 68. While it's not a perfect square, we can approximate its value or find its value using a calculator. The square root of 68 falls between the square roots of 64 (which is 8) and 81 (which is 9), so it will be a little more than 8. Therefore, we can order the numbers as follows: 7, 8, √68, 9. The correct sequence according to the options provided is thus 7, 8, √68, 9, which is Choice D.

User Aepheus
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