Question

A solution of 120 mL of 0.160 M KOH is mixed with a solution of 260 mL of 0.220 M NiSO4.

A) KOH is the limiting reactant.
B) NiSO4 is the limiting reactant.
C) Both reactants are completely used up.
D) Not enough information to determine.

Answer 1

To determine the limiting reactant in the given mixture, we compare the number of moles of each reactant and their stoichiometric coefficients.

Step-by-step explanation:

To determine the limiting reactant in this problem, we need to compare the number of moles of each reactant and their stoichiometric coefficients.

Let's start with KOH:

120 mL x 0.160 M = 19.2 mmol KOH

Next, let's calculate the number of moles of NiSO4:

260 mL x 0.220 M = 57.2 mmol NiSO4

Now, we divide the number of moles of each reactant by their stoichiometric coefficients:

KOH: 19.2 mmol KOH / 1 = 19.2 mmol KOH

NiSO4: 57.2 mmol NiSO4 / 1 = 57.2 mmol NiSO4

Since the number of moles of KOH is less than the number of moles of NiSO4, KOH is the limiting reactant.

Therefore, the correct answer is: A) KOH is the limiting reactant.