Question

While working at a snack bar, Jacqueline made $100 by selling 59 drinks. Sodas sold for $2 and Waters sold for $1.50. How many of each did Jacqueline sell?

A) 40 sodas and 19 waters
B) 30 sodas and 29 waters
C) 35 sodas and 24 waters
D) 45 sodas and 14 waters

Answer 1

Jacqueline sold 23 sodas and 36 waters, which is not listed among the options provided. The calculations were done by solving a system of linear equations using substitution or elimination.

Step-by-step explanation:

The student's question is about solving a system of linear equations. We are given a total revenue of $100 from selling 59 drinks, two types of drinks (sodas and waters) with different prices ($2 for sodas and $1.50 for waters), and we need to find out how many of each type were sold.

Let's define two variables: x for the number of sodas sold and y for the number of waters sold. We have two equations based on the given information:

1. x + y = 59 (total number of drinks sold)
2. 2x + 1.50y = 100 (total revenue from drinks)

By using the method of substitution or elimination, we can solve this system of equations to find the values of x and y. If we multiply the first equation by 1.50, we have 1.50x + 1.50y = 88.50. By subtracting this new equation from the second one, we can solve for x:

• (2x + 1.50y) - (1.50x + 1.50y) = 100 - 88.50
• 0.50x = 11.50
• x = 23

If x is 23, then using the first equation, y = 59 - 23, which is 36. So Jacqueline sold 23 sodas and 36 waters, which means the correct answer is not listed among the options provided.