Final answer:
To find the mass of water produced from 1 mole of oxygen gas, we calculate 2 moles of water times the molar mass of water (18.02 g/mol), which equals 36.04 grams.
Step-by-step explanation:
The question involves using stoichiometry to determine the mass of water (H2O) produced in a chemical reaction. Based on the stoichiometric coefficients provided, 2 moles of hydrogen gas (H2) react with 1 mole of oxygen gas (O2) to produce 2 moles of water. The molar mass of H2O is 18.02 g/mol. Therefore, for each mole of O2, 2 moles of H2O are produced, which is equivalent to 36.04 grams of H2O (2 moles × 18.02 g/mol).