Question

Using the density of methanol (d = 0.791 g/mL), calculate the volume of methanol, in mL, that corresponds to 5.0 g of methanol, and then calculate the volume of the 25% VN solution that contains this mass of methanol from its corresponding volume:

(A) Volume of 5.0 g of methanol: __________ mL
(B) Volume of the 25% VN solution: __________ mL

Answer 1

The volume of methanol that corresponds to 5.0 g of methanol is 6.3171 mL. This amount of methanol is contained in 25.2684 mL of a 25% V/V methanol solution.

Step-by-step explanation:

To calculate the volume of methanol corresponding to 5.0 g of methanol using the density of 0.791 g/mL, divide the mass by the density:

Volume of methanol = = (mass of methanol) / (density of methanol)

Volume of methanol = 5.0 g / 0.791 g/mL = 6.3171 mL

For the volume of the 25% V/V solution that contains 5.0 g of methanol, we calculate it as follows:

Volume of 25% solution = (Volume of methanol) / (percentage of methanol by volume)

Volume of 25% solution = 6.3171 mL / 0.25 = 25.2684 mL

Therefore, 6.3171 mL of methanol is present in 25.2684 mL of a 25% V/V methanol solution.