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A 100.-gram sample of H2O(l) at 22.0°C absorbs 830. joules of heat. What will be the final temperature of the water?

User Raffi
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Answer:23.976

Explanation:830j = 197.6 cal. 197.6/100g=1.976 degrees. plus 22 degrees =23.976

User Dusean Singh
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