Question

May you please help me solve the answer to this problem step by step, please?

Answer 1

Given:

As angle N is 90 degree.

`\begin{gathered} \angle N=44^(\circ)+\angle n \\ \angle n=90^(\circ)-44^(\circ) \\ \angle n=46^(\circ) \end{gathered}`

To find the bearing of flight from Elgin to Canton.

Use the sin ratio,

`\begin{gathered} (\sin c)/(510)=(\sin n)/(720) \\ (\sin c)/(510)=(\sin46^(\circ))/(720) \\ \sin c=(\sin46^(\circ))/(720)*510 \\ \sin c=0.4995 \\ c=\sin ^(-1)(0.5095) \\ c=30.63^(\circ) \end{gathered}`

The bearing angle ( clockwise from north ) can be calculated by subtracting the above angle from the west bearing angle of 270 degree.

`270^(\circ)-30.63^(\circ)=239.37^(\circ)`

Answer: 239.37 degree