Question

A silver wire with a 1mm diameter carries a charge of 90 C in 2 hours and 15 minutes. If silver contains 5.8x10^28 electrons per cube, what is the current flowing through the wire?

A) 1.25 A
B) 0.125 A
C) 0.0125 A
D) 12.5 A

Answer 1

The current flowing through a silver wire carrying a charge of 90 C in 2 hours and 15 minutes is calculated by dividing the charge by the time in seconds, resulting in approximately 0.0111 A, which is closest to 0.0125 A (option C).

Step-by-step explanation:

To calculate the current flowing through the silver wire, we will use the relation between charge (Q), current (I), and time (t).

Current is defined as charge per unit time, so the formula is:

I = Q / t

First, let's convert the time to seconds for uniformity since the charge is in coulombs and current is in amperes (coulombs per second).

2 hours and 15 minutes = (2 × 3600) + (15 × 60) seconds
= 7200 + 900 seconds
= 8100 seconds

Now, we can calculate the current using the formula:

I = 90 C / 8100 s
= 0.0111 A

Therefore, the correct answer is closest to option C, which is 0.0125 A.