Question

Hosting a lunch can be both stressful and algebraic. How could you represent this entire situation using an algebraic equation with variables to represent the number of pizzas and the number of bottles of soda?

A. Let (p) represent the number of pizzas and (s) represent the number of bottles of soda, (6p + 2s = 100).
B. Let (p) represent the number of bottles of soda and (s) represent the number of pizzas, (6s + 2p = 100).
C. Let (x) represent the number of pizzas and (y) represent the number of bottles of soda, (3x + 2y = 100).
D. There's not enough information to create an equation

Answer 1

Without additional context such as price per item or a relationship between pizzas and soda, it's impossible to accurately create an algebraic equation representing the situation, indicating that option D is correct.

Step-by-step explanation:

To represent the situation algebraically with variables for the number of pizzas and bottles of soda, we can create an equation that relates the two. However, from the provided information, we see that the equation Qs = 2 + 5P represents the quantity supplied of pizzas at a given price P, and the market operates where supply equals demand (Qd = Qs). Therefore, we need additional context such as the cost per pizza and per bottle of soda or a relationship between the two to write a specific equation for our scenario. Without these details, it's not possible to accurately create an equation like the ones provided in options A, B, or C, which likely indicates that D (There's not enough information to create an equation) is the correct answer. Nonetheless, this scenario serves as an excellent opportunity to practice making up one's own algebraic formula to further understand how equations capture concepts.