Question

The sum of three consecutive integers is 369. Find the integers.

A)121, 122, 123
B)122, 123, 124
C)121, 123, 125
D)123, 124, 125

Answer 1

The three consecutive integers whose sum is 369 are 122, 123, and 124. This is found by setting up an equation assuming the first integer is n; the sum of the integers is then expressed as n + (n+1) + (n+2) = 369, which simplifies to n = 122.

Step-by-step explanation:

To find the three consecutive integers whose sum is 369, we can denote the first integer as n, the second as n+1, and the third as n+2. Their sum is then written as:

n + (n+1) + (n+2) = 369

Simplifying, we get:

3n + 3 = 369

Subtracting 3 from both sides gives us:

3n = 366

Dividing both sides by 3 gives us:

n = 122

So the consecutive integers are 122, 123, and 124. This corresponds to option B) 122, 123, 124.